document.write( "Question 1123001: Two cars start at the same point and travel in opposite directions. The first car travels 10 miles per hour faster than the second car. In 3 hours, the cars are 270 miles apart. What is the rate of the second car? \n" ); document.write( "
Algebra.Com's Answer #739193 by ankor@dixie-net.com(22740)\"\" \"About 
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Two cars start at the same point and travel in opposite directions.
\n" ); document.write( " The first car travels 10 miles per hour faster than the second car.
\n" ); document.write( " In 3 hours, the cars are 270 miles apart.
\n" ); document.write( " What is the rate of the second car?
\n" ); document.write( ":
\n" ); document.write( "let s = the speed of the 2nd car
\n" ); document.write( "then
\n" ); document.write( "(s+10) = the speed of the 1st car
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation: dist = time * speed
\n" ); document.write( "3s + 3s(+10) = 270
\n" ); document.write( "3s + 3s + 30 = 270
\n" ); document.write( "6s = 270 - 30
\n" ); document.write( "s = 240/6
\n" ); document.write( "s = 40 mph the 2nd car
\n" ); document.write( "then, obviously
\n" ); document.write( "10 + 40 = 50 mpn the 1st car
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check, find the actual dist each car travels
\n" ); document.write( "3*40 = 120 mi
\n" ); document.write( "3*50 = 150 mi
\n" ); document.write( "-----------------
\n" ); document.write( "total: 270 mi
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