document.write( "Question 1122981: Find the resultant force R that will balance the three forces by adding a fourth mass to the force table at the appropriate angle.
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Algebra.Com's Answer #739174 by Edwin McCravy(20054) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "   x-components:                     y-components\r\n" );
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document.write( "300∙cos(30°)  =  259.81          300∙sin(30°)  =  150.00\r\n" );
document.write( "450∙cos(110°) = -153.91          450∙sin(110°) =  422.86\r\n" );
document.write( "400∙cos(230°) = -257.12          400∙sin(230°) = -306.42 \r\n" );
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document.write( "Total x-comp. = -151.22          Total y-comp. =  266.44\r\n" );
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document.write( "resultant magnitude =  = 306.36\r\n" );
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document.write( "tan(resultant angle) = \r\n" );
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document.write( "Since x-comp negative and y-comp positive,\r\n" );
document.write( "resultant is in Quadrant II, so \r\n" );
document.write( "Resultant angle = 119.6°\r\n" );
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document.write( "So the force that will balance the three forces is a force\r\n" );
document.write( "equal in magnitude to their resultant and in the opposite\r\n" );
document.write( "direction, so we add 180° to the angle and the answer is\r\n" );
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document.write( "306.36g @ 299.6°\r\n" );
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document.write( "Note: The balancing force is NOT the resultant force, but\r\n" );
document.write( "is in the opposite direction from the resultant force.  That's\r\n" );
document.write( "why I added 180° to the angle.  You might mention this to your \r\n" );
document.write( "teacher.\r\n" );
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document.write( "Edwin

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