document.write( "Question 1122931: How do I graph Linear equations such as:\r
\n" ); document.write( "\n" ); document.write( "3x + y = -1
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Algebra.Com's Answer #739110 by Boreal(15235)\"\" \"About 
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Several ways.
\n" ); document.write( "let x=0 and y=-1, so (0, -1) is one point.
\n" ); document.write( "Now let y=0 and 3x=-1, so x=-(1/3) and (-1/3, 0) is another point.
\n" ); document.write( "Draw a line between the two points.\r
\n" ); document.write( "\n" ); document.write( "Slope-intercept form of y=mx+b where m is the slope (rise/run) and b the y-intercept, or where x=0.
\n" ); document.write( "move the 3x to the right
\n" ); document.write( "y=-3x-1
\n" ); document.write( "line has y-intercept of -1, so (0, -1) is a point.
\n" ); document.write( "slope is -3.
\n" ); document.write( "From -1 go right 1 and down 3 or left 1 and up 3. Draw a line.
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