document.write( "Question 1122916: The quotient of two numbers is 4 and there difference is 39 what is the smaller number of that to \n" ); document.write( "
Algebra.Com's Answer #739099 by MathLover1(20855)\"\" \"About 
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\n" ); document.write( "let's numbers be \"x\" and \"y\"\r
\n" ); document.write( "\n" ); document.write( "given:
\n" ); document.write( "the quotient of two numbers is \"4\" which meas\r
\n" ); document.write( "\n" ); document.write( " \"x%2Fy=4\"...eq.1\r
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\n" ); document.write( "\n" ); document.write( " and there difference is \"39\" which meas\r
\n" ); document.write( "\n" ); document.write( "\"x-y=39\"...eq.2\r
\n" ); document.write( "\n" ); document.write( "start with eq.1 and solve it for \"x\":\r
\n" ); document.write( "\n" ); document.write( "\"x%2Fy=4\"...eq.1\r
\n" ); document.write( "\n" ); document.write( "\"x=4y\"...eq.1a\r
\n" ); document.write( "\n" ); document.write( "go to eq.2, substitute \"x\" from eq.1a\r
\n" ); document.write( "\n" ); document.write( "\"4y-y=39\"\r
\n" ); document.write( "\n" ); document.write( "\"3y=39\"\r
\n" ); document.write( "\n" ); document.write( "\"y=39%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"y=13\"\r
\n" ); document.write( "\n" ); document.write( "go back to eq.1a, find \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=4%2A13\"\r
\n" ); document.write( "\n" ); document.write( "\"x=52\"\r
\n" ); document.write( "\n" ); document.write( "so, your numbers are: \"13\" (the smaller number) and \"52\"\r
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