document.write( "Question 101511This question is from textbook Intermediate Algebra
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document.write( ": Can someone please help me factor this problem completely?
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document.write( "x^10y^3 - 4x^9y^2 - 21x^8y?????\r
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document.write( "Here is what I have as my attempt, but am not sure I am even correct with what I have..
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document.write( "Simplify:
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document.write( "x^10y^3 - 36xy^2 - 168xy
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document.write( "x^10y^3 - 72xy - 168xy\r
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document.write( "Combine like terms:
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document.write( "72xy + 168xy = 240xy\r
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document.write( "240xy* x^10*y^3=?\r
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document.write( "This problem was given to me by my college Professor, but it is not from our textbook. Thanks. Below are additional directions from Professor:\r
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document.write( "**Make sure to superscript all exponents. If you believe that a polynomial is not factorable, label it as prime. Show all stages of factoring separately (i.e., show the result of factoring out a GCF before taking the resulting polynomial and factoring it again).**\r
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Algebra.Com's Answer #73909 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Given: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "First look at the numbers that multiply each of the terms to see if there is are common \n" ); document.write( "factors. The first term is multiplied by 1 (understood), the second term by -4, and the \n" ); document.write( "third term by -21. These three numbers have no common factors, so we don't change them. \n" ); document.write( ". \n" ); document.write( "Next look at the x part of each of the terms. The first term contains \n" ); document.write( "term \n" ); document.write( " \n" ); document.write( "we get:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Next notice that you have a \"y\" common to all terms. So pull a y out as a multiplier and \n" ); document.write( "you have: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Notice that we can multiply out \n" ); document.write( "the original given expression. This is just a \"check\". \n" ); document.write( ". \n" ); document.write( "So we are down to \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "We can try to factor this into (A + ___)*(A + ___). The underscores have to be two numbers \n" ); document.write( "that are factors of -21. These numbers could be 21 and 1 or 7 and 3. With their appropriate signs \n" ); document.write( "they must sum to -4. -7 and + 3 do that. If they are multiplied they give -21 and if they are \n" ); document.write( "added they give -4 which is the multiplier of the center term that contains just A. \n" ); document.write( ". \n" ); document.write( "So we can write that \n" ); document.write( "that we said A was equal to xy. So now we can substitute xy into the two factors and get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "And so we can say that \n" ); document.write( "carry this result back into this equation that we got earlier: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "In this equation, replace \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and that's the answer to your problem. \n" ); document.write( ". \n" ); document.write( "I know this is confusing, but I hope that you can see your way through it. If you can \n" ); document.write( "understand all the maneuvering in this you will have made a lot of progress. \n" ); document.write( " |