document.write( "Question 1122892: Ben finish a job 2 hours longer than Daniel. After Ben had been working for 1 hour Daniel joined him and they completed the remaining portion of the job for 3 hours. How long would it take Ben to do the job? \n" ); document.write( "
Algebra.Com's Answer #739070 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Ben finish a job 2 hours longer than Daniel. \n" ); document.write( " After Ben had been working for 1 hour Daniel joined him and they completed the remaining portion of the job for 3 hours. \n" ); document.write( " How long would it take Ben to do the job? \n" ); document.write( ": \n" ); document.write( "d = time required by Daniel to complete the job \n" ); document.write( "\"Ben finish a job 2 hours longer than Daniel.\" \n" ); document.write( "(d+2) = time required by Ben \n" ); document.write( "Let the completed job = 1 \n" ); document.write( ": \n" ); document.write( "After Ben had been working for 1 hour Daniel joined him and they completed the remaining portion of the job for 3 hours. \" \n" ); document.write( "Ben worked 4 hrs, Daniel worked 3 hrs \n" ); document.write( ": \n" ); document.write( "A shared work equation \n" ); document.write( " \n" ); document.write( "multiply equation by d(d+2) \n" ); document.write( "4d + 3(d+2) = d(d+2) \n" ); document.write( "4d + 3d + 6 = d^2 + 2d \n" ); document.write( "7d + 6 = d^2 + 2d \n" ); document.write( "form a quadratic equation on the right \n" ); document.write( "0 = d^2 + 2d - 7d - 6 \n" ); document.write( "d^2 - 5d - 6 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(d-6)(d+1) = 0 \n" ); document.write( "the positive solution \n" ); document.write( "d = 6 hrs Daniel working time alone \n" ); document.write( "and obviously \n" ); document.write( "8 hrs Ben working alone \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "check \n" ); document.write( " |