document.write( "Question 1122872: Five years ago Nicole was three times as old as Rianne. Five years hence, Nicole will be twice as old as Rianne. Find their present ages. \n" ); document.write( "

Algebra.Com's Answer #739051 by ikleyn(52914) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "

\r\n" );
document.write( "From the condition, you have these two equations\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "N - 5 = 3*(R-5)        (1)    (\"Five years ago Nicole was three times as old as Rianne.\")\r\n" );
document.write( "N + 5 = 2*(R+5)        (2)    (\"Five years hence . . . \" )\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "N - 5 = 3R - 15        (3)\r\n" );
document.write( "N + 5 = 2R + 10        (4)\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Subtract eq(3) from eq(4). You will get\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "10 = -R + 10 - (-15)\r\n" );
document.write( "\r\n" );
document.write( "10 = -R + 25\r\n" );
document.write( "\r\n" );
document.write( "10 - 25 = -R  ====>  R = 15.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Answer.  R is 15 years old.  N is (from eq(4) )   N = 2R + 10-5 = 2*15+10-5 = 35 years old.\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );