document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=101363>Question 101363</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Showing algebra....\r<BR>\n" );
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document.write( "A pile of coin 15 coins contains dimes and quaters.  If the value of the pile is $1.65 find the number of dimes and quaters in the pile. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73904 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73904\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=number of quarters<BR>\n" );
document.write( "value of the quarters=0.25x\r<BR>\n" );
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document.write( "Then 15-x=number of dimes<BR>\n" );
document.write( "value of the dimes=0.10(15-x)\r<BR>\n" );
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document.write( "Now we are told that the value of the quarters plus the value of the dimes equals $1.65, so:\r<BR>\n" );
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document.write( "0.25x+0.10(15-x)=1.65  get rid of parens\r<BR>\n" );
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document.write( "0.25x+1.5-0.10x=1.65  subtract 1.5 from both sides<BR>\n" );
document.write( "0.25x+1.5-1.5-0.10x=1.65-1.5  collect like terms\r<BR>\n" );
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document.write( "0.15x=0.15   divide both sides by 0.15\r<BR>\n" );
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document.write( "x=1---------------------------number of quarters\r<BR>\n" );
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document.write( "15-x=15-1=14-----------------------number of dimes\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "0.25*1+0.10*14=$1.65<BR>\n" );
document.write( "0.25+1.40=1.65<BR>\n" );
document.write( "1.65=1.65\r<BR>\n" );
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document.write( "Hope this helps----ptaylor </SPAN>\n" );
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