document.write( "Question 1122811: Point B belongs to AC so that AB:BC=2:1. Point D belongs to AB so that AD:DB=3:2. Find AD:DC? \n" ); document.write( "
Algebra.Com's Answer #739028 by ankor@dixie-net.com(22740)\"\" \"About 
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Point B belongs to AC so that AB:BC=2:1.
\n" ); document.write( " Point D belongs to AB so that AD:DB=3:2. Find AD:DC?
\n" ); document.write( ":
\n" ); document.write( "let x = the first multiplier
\n" ); document.write( "let y = the 2nd multiplier
\n" ); document.write( "A------------D-------B--------C
\n" ); document.write( "AB = 2x
\n" ); document.write( "BC = x
\n" ); document.write( "AC = 3x
\n" ); document.write( ":
\n" ); document.write( "AD = 3y
\n" ); document.write( "DB = 2y
\n" ); document.write( "AB = 5y
\n" ); document.write( "therefore
\n" ); document.write( "2x = 5y
\n" ); document.write( "x = \"5%2F2\"y
\n" ); document.write( "x = 2.5y
\n" ); document.write( ";
\n" ); document.write( "Find AD:DC?
\n" ); document.write( "AD = 3y,
\n" ); document.write( "DC = 3x - 3y
\n" ); document.write( "replace x with 2.5y
\n" ); document.write( "DC = 3(2.5y-3y)
\n" ); document.write( "DC = 7.5y - 3y
\n" ); document.write( "DC = 4.5y
\n" ); document.write( ":
\n" ); document.write( "\"%28AD%29%2F%28DC%29\" = \"%283y%29%2F%284.5Y%29\" = 2:3 is AD:DC
\n" ); document.write( "
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