document.write( "Question 1122811: Point B belongs to AC so that AB:BC=2:1. Point D belongs to AB so that AD:DB=3:2. Find AD:DC? \n" ); document.write( "
Algebra.Com's Answer #739028 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Point B belongs to AC so that AB:BC=2:1. \n" ); document.write( " Point D belongs to AB so that AD:DB=3:2. Find AD:DC? \n" ); document.write( ": \n" ); document.write( "let x = the first multiplier \n" ); document.write( "let y = the 2nd multiplier \n" ); document.write( "A------------D-------B--------C \n" ); document.write( "AB = 2x \n" ); document.write( "BC = x \n" ); document.write( "AC = 3x \n" ); document.write( ": \n" ); document.write( "AD = 3y \n" ); document.write( "DB = 2y \n" ); document.write( "AB = 5y \n" ); document.write( "therefore \n" ); document.write( "2x = 5y \n" ); document.write( "x = \n" ); document.write( "x = 2.5y \n" ); document.write( "; \n" ); document.write( "Find AD:DC? \n" ); document.write( "AD = 3y, \n" ); document.write( "DC = 3x - 3y \n" ); document.write( "replace x with 2.5y \n" ); document.write( "DC = 3(2.5y-3y) \n" ); document.write( "DC = 7.5y - 3y \n" ); document.write( "DC = 4.5y \n" ); document.write( ": \n" ); document.write( " |