document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=101398>Question 101398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The following are from the Compass sample test.<BR>\n" );
document.write( "Algebra Placement<BR>\n" );
document.write( "Linear equations\r<BR>\n" );
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document.write( "15.What is the slope of the line with the equation 2x+3y+6=0\r<BR>\n" );
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document.write( "Please explain how to get to the answer of -2/3\r<BR>\n" );
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document.write( "16. Point A (-4,1) is in the standard (x,y) coordinate plane. What must be the coordinates of point B so that the line x=2 is the perpendicular bisector of AB?\r<BR>\n" );
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document.write( "Please explain how to get to the answer of (8,1)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73902 by </B><A HREF=/tutors/aboutme.mpl?userid=doukungfoo><B>doukungfoo(195)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=doukungfoo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=doukungfoo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 15.What is the slope of the line with the equation 2x+3y+6=0\r<BR>\n" );
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document.write( "To find the slope we need to convert this equation to the slope intercept form which is:<BR>\n" );
document.write( "y=mx+b<BR>\n" );
document.write( "m is the slope and b is y intercept.<BR>\n" );
document.write( "2x + 3y + 6 = 0<BR>\n" );
document.write( "first move 2x to the right side of the equation<BR>\n" );
document.write( "This is done by subtracting 2x from both sides<BR>\n" );
document.write( "2x - 2x + 3y + 6 = 0-2x<BR>\n" );
document.write( "on the left side 2x-2x cancel out and on the right side 0-2x leaves -2x so we get this<BR>\n" );
document.write( "3y + 6 = -2x<BR>\n" );
document.write( "next move 6 following the same procedure<BR>\n" );
document.write( "3y + 6 - 6 = -2x - 6<BR>\n" );
document.write( "3y = -2x - 6<BR>\n" );
document.write( "finally isolate y by dividing by 3 across the equation<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-%282%2F3%29x-2%29 ALIGN=MIDDLE  ALT=\"y=-%282%2F3%29x-2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now that we have convert the equation to slope intercept form we can identify the slope, which is:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-2%2F3%29 ALIGN=MIDDLE  ALT=\"-2%2F3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "16. Point A (-4,1) is in the standard (x,y) coordinate plane. What must be the coordinates of point B so that the line x=2 is the perpendicular bisector of AB?\r<BR>\n" );
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document.write( "For this one I would just plot the information given on a graph.<BR>\n" );
document.write( "First plot point A at (-4,1) Then draw the line x=2 which is a vertical line that crosses the x axis at 2. Once we have done this we can see that point A is 6 units away from the the line x=2 so point B must be 6 units away on the x axis for line x=2 to be a bisector of line segement AB. Also point B must have the same x intercept as point A for line segment AB to be perpendicular to line x=2. The only point on the graph that meets these requirements is (8,1)\r<BR>\n" );
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