document.write( "Question 101498: The sum of the squares of two consecutive integers is 41. What is the larger integer? \n" ); document.write( "
Algebra.Com's Answer #73895 by edjones(8007)\"\" \"About 
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let the integers be x and x+1
\n" ); document.write( "x^2 + (x+1)^2=41
\n" ); document.write( "x^2+x^2+2x+1=41
\n" ); document.write( "2x^2+2x-40=0
\n" ); document.write( "2(x^2+x-20)=0
\n" ); document.write( "2(x+5)(x-4)=0 Factor
\n" ); document.write( "x=4 , x=-5
\n" ); document.write( "the problem has two answers.
\n" ); document.write( "-5, -4
\n" ); document.write( "and 5, 4
\n" ); document.write( "4 and -5 the smaller integers.
\n" ); document.write( "x+1= 5 and -4 are the larger integers. ANSWER
\n" ); document.write( "Ed
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