document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1122750>Question 1122750</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write an equation in&#8203; slope-intercept form for the line described.<BR>\n" );
document.write( "&#8203;x-intercept -5&#8203;, &#8203;y-intercept 8\r<BR>\n" );
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document.write( "Find an equation for the line which passes through &#8203;(-2&#8203;,3&#8203;) and is perpendicular to the line containing &#8203;(0,3&#8203;) and &#8203;(3&#8203;,6&#8203;).\r<BR>\n" );
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document.write( "Find an equation of the line having the given slope and containing the given point.<BR>\n" );
document.write( "m = 4/5, &#8203;(6&#8203;,-6&#8203;) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #738910 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=738910\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=mx+b, m is slope and b the y-value of the y-intercept (x=0)<BR>\n" );
document.write( "slope goes between points (-5, 0) and (0, 8), and that is a slope of (8-0)/0-(-5)) or 8/5<BR>\n" );
document.write( "y=(8/5)x+8<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C1.6x%2B8%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C1.6x%2B8%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "perpendicular lines have product of slopes = -1<BR>\n" );
document.write( "line given has slope of 3/3 or 1<BR>\n" );
document.write( "line desired has slope of -1<BR>\n" );
document.write( "point slope formula y-y1=m(x-x1), m slope and (x1, y1) point<BR>\n" );
document.write( "Line containing (0, 3) and (3, 6) can be plotted to show y=x+3<BR>\n" );
document.write( "perpendicular line has slope -1<BR>\n" );
document.write( "point slope formula y-y1=m(x-x1), m slope and (x1, y1) point<BR>\n" );
document.write( "y-3=(-1)(x+2)<BR>\n" );
document.write( "y=-x+1<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C-x%2B1%2Cx%2B3%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C-x%2B1%2Cx%2B3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "point slope formula y-y1=m(x-x1), m slope and (x1, y1) point<BR>\n" );
document.write( "y+6=(4/5)(x-6)<BR>\n" );
document.write( "y+6=(4/5)x-(24/5)<BR>\n" );
document.write( "y=(4/5)x-(54/5) </SPAN>\n" );
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