document.write( "Question 1122733: A rectangular lot whose perimeter is 270 ft is fenced along three sides. An expensive fencing along the​ lot's length cost $ 24 per foot. An inexpensive fencing along the two side widths costs only $ 4 per foot. The total cost of the fencing along the three sides comes to $ 2280. What are the​ lot's dimensions? \n" ); document.write( "
Algebra.Com's Answer #738900 by ikleyn(52788)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "Let W be the width, in feet.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Then the length is  (135-W) ft.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The money equation is\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "4*(2W) + 24*(135-W) = 2280.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Simplify and solve for W:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "8W + 24*135 - 24W = 2280\r\n" );
document.write( "\r\n" );
document.write( "24*135 - 2280 = 24W - 8W \r\n" );
document.write( "\r\n" );
document.write( "960 = 16W  ====>  W = \"960%2F16\" = 60.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Anwer.  The width is 60 ft;  the length is 135-60 = 75 ft.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Check.  Perimeter = 2*(60 + 75) = 270 ft.             ! Correct ! \r\n" );
document.write( "\r\n" );
document.write( "        The cost = 4*(2*60) + 24*75 = 2280 dollars.   ! Correct ! \r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "===============\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Be aware !   The solution by  @Boreal  is incorrect.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );