document.write( "Question 1122735: The sum of any n consecutive integers is always equal to 100 less than the sum of the next n consecutive integers. Find n \n" ); document.write( "

Algebra.Com's Answer #738896 by Boreal(15235) $\"\"$ $\"About$

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If it is 100 less, than there will be 100 integers, each 1 less than the corresponding one in the smaller group. The other way to look at it is by comparing lists of both, the second group's having 2 over 100 and 98 under 100, and the largest is exactly 100 more than the smallest.
\n" ); document.write( "sum of integers from 1 to 100 is (1/2)(n*(n+1))=5050, when n=100
\n" ); document.write( "sum of integers from 1 to 101 is 5151 or (1/2)(101*102). Therefore, sum of the integers from 2 to 101 is 5150\r
\n" ); document.write( "\n" ); document.write( "n=100. \n" ); document.write( "

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