document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1122736>Question 1122736</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the measurement of both complementary angles<BR>\n" );
document.write( "One of them is 3 times less than the other </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #738895 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=738895\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Complementary angles add to 90 deg<BR>\n" );
document.write( "let  DISABLED_event_one= x<BR>\n" );
document.write( "the other =3x  (can use x and (1/3) x but introduces fractions)<BR>\n" );
document.write( "x+3x=4x=90 deg<BR>\n" );
document.write( "x=22.5 deg<BR>\n" );
document.write( "3x=67.5 deg </SPAN>\n" );
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