document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1122715>Question 1122715</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the derivative of the following function:<BR>\n" );
document.write( "y=(2x-3)(x^3 -2)^1/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #738871 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=738871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is (2x-3)*(1/3)(x^3-2)^(-2/3)*3x^2 + (x^3-2)^(1/3)*2x, using the chain rule<BR>\n" );
document.write( "=x^2(2x-3)/(x^3-2)^(2/3) + 2x(x^3-2)^(1/3).  There are other ways to rewrite this. </SPAN>\n" );
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