document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=101471>Question 101471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I AM NOT SUER HOW TO WORK THIS PROBLEM SOLVING FOR Y.Y-1=-2/3(X+6). FIRST I GET RID OF THE FRACTION BY MULTIPLYING BY 3 WHICH CROSSES OUT ON THE 2/3 AND LEAVES 2. Y-1=2/3(X+6)= 3Y-1=2X+12 = 3Y=2X+12+1 DIVIDED BY 3= Y=2/3X+4-3 WHICH IS WRONG.WHAT AM I DOING WRONG\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73886 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73886\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SOLVING FOR Y.Y-1=-2/3(X+6). <BR>\n" );
document.write( "y = (2/3)(x+6)+1<BR>\n" );
document.write( "y = (2/3)x + 4+1<BR>\n" );
document.write( "y = (2/3)x + 5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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