document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1122716>Question 1122716</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the derivative of the following function:<BR>\n" );
document.write( "y=(2x+1/2x-1)^1/2\r<BR>\n" );
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document.write( "y=sin3t/(t+1)^1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #738858 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=738858\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It is (1/2)[(2x+1)/(2x-1)]^(-1/2) * derivative of (2x+1)/(2x-1)<BR>\n" );
document.write( "That derivative is  {1/(2x-1)^2}}*(2x-1)*2-(2x+1)(2)=-4/(2x-1)^2<BR>\n" );
document.write( "={(-2)/2x-1)^2}*1/sqrt((2x+1)/(2x-1))<BR>\n" );
document.write( "The -4 becomes -2 because of the (1/2) in the first part of the derivative. </SPAN>\n" );
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