document.write( "Question 1122626: Hi\r
\n" ); document.write( "\n" ); document.write( "2 similar containers P and Q were filled with rice and beans. The ratio of rice to beans in P and Q were 1:5 & 5:3 respective ly. Jug R contained 620g of beans when all the beans from P and Q were poured into R there were 1200g of beans altogether. How many grams of rice were in P.\r
\n" ); document.write( "\n" ); document.write( "Thanks
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Algebra.Com's Answer #738846 by greenestamps(13206)\"\" \"About 
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\n" ); document.write( "Mathematically, \"similar\" containers means the two containers are the same shape but can be different sizes. If that were, the case, the problem could not be solved. So I assume you mean containers P and Q are identical.

\n" ); document.write( "The contents of container P are divided into 6 parts (1:5 rice to beans); the contents of Q are divided into 8 parts (5:3 rice to beans). The problem is most easily worked if we use a common denominator of 6 and 8 so that we can visualize the two containers divided into equal numbers of parts.

\n" ); document.write( "The least common denominator of 6 and 8 is 24. So consider container P to have 4 parts rice and 20 parts beans (a 1:5 ratio), and consider container Q to have 15 parts rice and 9 parts beans (a 5:3 ratio).

\n" ); document.write( "So together containers P and Q have 20+9=29 parts beans and 4+15=19 parts rice. When the 29 parts beans from P and Q are added to the 620g of beans already in R, there are 1200g of beans in R. So

\n" ); document.write( "\"620%2B29x+=+1200\"
\n" ); document.write( "\"29x+=+580\"
\n" ); document.write( "\"x+=+20\"

\n" ); document.write( "Each \"part\" of each container is 20g.

\n" ); document.write( "The question asks for the number of grams of rice in P. P has 4 parts rice, which is 4*20 = 80g.

\n" ); document.write( "Answer: P had (has) 80g of rice.
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