document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=101413>Question 101413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve 2x^2-3x-14=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73884 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73884\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first approach is to try to factor it.\r<BR>\n" );
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document.write( "You know you will have:  (2x   )(x    ) for the x terms.  And since the constant is negative, one of the factors will have a - and the other will have a +.\r<BR>\n" );
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document.write( "You know that 14 = 2 * 7, which are your only choices.\r<BR>\n" );
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document.write( "So the only choices are<BR>\n" );
document.write( "(2x + 2)(x - 7)<BR>\n" );
document.write( "(2x - 2)(x + 7)<BR>\n" );
document.write( "(2x + 7)(x - 2)<BR>\n" );
document.write( "(2x - 7)(x + 2)\r<BR>\n" );
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document.write( "You're looking to the -3x, which is:'\r<BR>\n" );
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document.write( "(2x - 7)(x + 2)\r<BR>\n" );
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document.write( "ALWAYS check!<BR>\n" );
document.write( "(2x - 7)(x + 2) = 2x*x + 2x*2 - 7*x - 7*2 = 2x^2 + 4x - 7x - 14 = 2x^2 - 3x - 14. </SPAN>\n" );
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