document.write( "Question 1122615: . x + 3y − z = a
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document.write( "x + y + 2z = b
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document.write( "2y − 3z = c
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document.write( "solve the following systems, where a, b,
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document.write( "and c are constants. \n" );
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Algebra.Com's Answer #738749 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! ------------------------------------- \n" ); document.write( ". x + 3y − z = a \n" ); document.write( "x + y + 2z = b \n" ); document.write( "2y − 3z = c \n" ); document.write( "-------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From first two equations, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Revision to simpler system: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Returning to \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Add corresponding members, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "from the very first equation, \n" ); document.write( "substitute for y and z, simplify from that. \n" ); document.write( " |