document.write( "Question 1122550: A box contains nine chocolates -- four with pecans, three with coconut, and two with raspberry creme. Spider-Man eats three of the chocolates, chosen randomly. What's the probability that he eats (exactly) two with coconut?
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Algebra.Com's Answer #738694 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "A box contains nine chocolates -- four with pecans, three with coconut, and two with raspberry creme.
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\n" ); document.write( "\n" ); document.write( " The solution by the tutor @greenestamps was not exactly correct,\r
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document.write( "1.  Notice that 4 + 3 + 2 = 9 chocolates.\r\n" );
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document.write( "2.  The number of all possible triples of chocolates is   =  = 84.\r\n" );
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document.write( "    It is the number of all elements in the \"space events\".\r\n" );
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document.write( "3.  Spider-man can choose 2 of 3 coconut chocolates by   = 3 ways, and then he can add any of remaining NON-COCONUT chocolates by 4+2 = 6 ways.\r\n" );
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document.write( "    It gives him  3*6 = 18 ways to get 3 chocolates under the condition imposed by the problem.\r\n" );
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document.write( "4.  So the answer to the problem question is   = .\r\n" );
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