document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1122552>Question 1122552</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Show, that if p and q are two solutions of a quadratic equation ax^2 + bx + c = 0 (a cannot equal zero) then p + q = -b/a and p * q = c/a\r<BR>\n" );
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document.write( "I would really appreciate help with this problem! <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #738679 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=738679\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use the quadratic formula for roots, then<BR>\n" );
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document.write( "p = (-b +sqrt(b^2 -4ac))/2a<BR>\n" );
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document.write( "q = (-b -sqrt(b^2 -4ac))/2a<BR>\n" );
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document.write( "p+q = ((-b +sqrt(b^2 -4ac) +(-b -sqrt(b^2 -4ac)))/2a =<BR>\n" );
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document.write( "-2b/2a = <BR>\n" );
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document.write( "-b/a<BR>\n" );
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document.write( "p*q = (-b +sqrt(b^2 -4ac))/2a * (-b -sqrt(b^2 -4ac))/2a =<BR>\n" );
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document.write( "(b^2 -b^2 +4ac)/4a^2 =<BR>\n" );
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document.write( "4ac/4a^2 =<BR>\n" );
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document.write( "c/a<BR>\n" );
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