document.write( "Question 1122514: The sum of an infinite G.P. is 15 and the sum of the squares of the terms is 45. Find the G.P \n" ); document.write( "
Algebra.Com's Answer #738653 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Let the GP be

\n" ); document.write( "a, ar, ar^2, ar^3, ...

\n" ); document.write( "Then the GP with the terms squared is

\n" ); document.write( "a^2, a^2r^2, a^2r^4, a^2r^6, ...

\n" ); document.write( "The infinite sum of the GP is

\n" ); document.write( "(1) \"a%2F%281-r%29+=+15\"

\n" ); document.write( "The infinite sum of the squared GP is

\n" ); document.write( "(2) \"a%5E2%2F%281-r%5E2%29+=+45\"

\n" ); document.write( "Dividing (2) by (1) gives us

\n" ); document.write( "(3) \"a%2F%281%2Br%29+=+3\"

\n" ); document.write( "Then (1) and (3) give us two linear equations in a and r that we can solve:

\n" ); document.write( "\"a+=+15-15r\"
\n" ); document.write( "\"a+=+3%2B3r\"
\n" ); document.write( "\"15-15r+=+3%2B3r\"
\n" ); document.write( "\"12+=+18r\"
\n" ); document.write( "(4) \"r+=+2%2F3\"

\n" ); document.write( "Then substituting (4) in (1) gives us a=5.

\n" ); document.write( "The GP has first term 5 and common ratio 2/3:

\n" ); document.write( "5, 10/3, 20/9, ...

\n" ); document.write( "The squared GP is

\n" ); document.write( "25, 100/9 400/81, ...

\n" ); document.write( "CHECK:

\n" ); document.write( "The sum of the GP is

\n" ); document.write( "\"5%2F%281-%282%2F3%29%29+=+5%2F%281%2F3%29+=+15%29\"

\n" ); document.write( "The sum of the squared GP is

\n" ); document.write( "\"25%2F%281-%284%2F9%29%29+=+25%2F%285%2F9%29+=+45\"

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