document.write( "Question 1122512: Roberto Invested a total of $10,000 apart at 6% in part and 9% how much did you invest in the lower interest account if the total interest earned in one year was $810? \n" ); document.write( "
Algebra.Com's Answer #738638 by Shin123(626)\"\" \"About 
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Let a be the amount at 6% and b be the amount at 9%.\r
\n" ); document.write( "\n" ); document.write( "\"system%280.06a%2B0.09b=810%2Ca%2Bb=10000%29\"\r
\n" ); document.write( "\n" ); document.write( "\"system%280.02a%2B0.03b=270%2Ca%2Bb=10000%29\"\r
\n" ); document.write( "\n" ); document.write( "\"system%28a%2B1.5b=13500%2Ca%2Bb=10000%29\" Subtract the 2 equations to get\r
\n" ); document.write( "\n" ); document.write( "\"0.5b=3500\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28b=7000%29\" That means a equals 10000-7000=3000\r
\n" ); document.write( "\n" ); document.write( "\"system%28a=3000%2Cb=7000%29\" Check: 3000*0.06=180 7000*0.09=630 180+630=810. Correct!
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