document.write( "Question 1122487: Ndiba left the mall and traveled toward the lake. Two hours later Emily left traveling at 70 km/h in an effort to catch up to Ndiba. After traveling for three hours Emily finally caught up. What was Ndiba's average speed.
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Algebra.Com's Answer #738636 by josmiceli(19441)\"\" \"About 
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Let \"+s+\" = Ndiba’s average speed
\n" ); document.write( "\"+s%2A2+\" = distance Ndiba travels before Emily leaves
\n" ); document.write( "Let \"+d+\" = distance Emily travels until they meet
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\n" ); document.write( "Neiba’s equation:
\n" ); document.write( "(1) \"+d+-+2s+=+s%2A3+\"
\n" ); document.write( "Emily’s equation:
\n" ); document.write( "(2) \"+d+=+70%2A3+\"
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\n" ); document.write( "(1) \"+d+=+5s+\"
\n" ); document.write( "And
\n" ); document.write( "(2) \"+5s+=+70%2A3+\"
\n" ); document.write( "(2) \"+s+=+42+\"
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\n" ); document.write( "Ndiba’s average speed is 42 km/hr
\n" ); document.write( "Check:
\n" ); document.write( "In 1st 2 hrs N traveled \"+s%2A2+=+84+\" km
\n" ); document.write( "In next 3 hrs she traveled \"+s%2A1+=+126+\" km
\n" ); document.write( "\"+84+%2B+126+=+210+\" which was Emily’s distance
\n" ); document.write( "Since \"+d+=+70%2A3+\"
\n" ); document.write( "Get 2nd opinion if needed\r
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