document.write( "Question 1122474: A cattle train left Abuja and traveled toward the outer-most station. A diesel train left 13 hours later traveling 65 km/h faster in an effort to catch up to it. After three hours the diesel train finally caught up. What was the cattle train's average speed.
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Algebra.Com's Answer #738609 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "Let x be the cattle train average speed (the value under the question.\r\n" );
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document.write( "Then the diesel train speed is (x+65) km/h, according to the condition.\r\n" );
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document.write( "The cattle train was on the way for 13+3 = 16 hours and covered the distance of 16*x kilometers\r\n" );
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document.write( "The diesel train was on the way for 3 hours and covered the distance of 3*(x+65) kilometers.\r\n" );
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document.write( "The distance is the same, which gives you an equation\r\n" );
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document.write( "3*(x+65) = 16*x   kilometers.\r\n" );
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document.write( "3x + 3*65 =  16x\r\n" );
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document.write( "3*65 = 16x - 3x\r\n" );
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document.write( "3*65 = 13x  ====>  x =  = 3*5 = 15.\r\n" );
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document.write( "Answer.  The cattle train average speed was  15 km/h.\r\n" );
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\n" ); document.write( "\n" ); document.write( "See introductory lessons on Travel and Distance problems\r
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\n" ); document.write( "\n" ); document.write( "You will find the solutions of many similar problems there.\r
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\n" ); document.write( "\n" ); document.write( "Read them and learn once for all from these lessons on how to solve simple Travel and Distance problems.\r
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