document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1122418>Question 1122418</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.Suppose the weights of packages of lettuce coming off a packaging line have a normal distribution with mean 8.1 ounces and standard deviation .1 ounce. \r<BR>\n" );
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document.write( "What is the probability that a package of lettuce came off the packaging line weigh more than 8.25 ounces? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #738558 by </B><A HREF=/tutors/aboutme.mpl?userid=FrankM><B>FrankM(1040)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FrankM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=FrankM><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=738558\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> With a standard deviation of .1 oz, the question simplifies to \r<BR>\n" );
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document.write( "\"what is the area to the right of 1.5 standard deviations from the median?\" See how 8.25-8.1=.15? And .15/.1 is 1.5? This is 1.5 STDEV away from median.\r<BR>\n" );
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document.write( "We need to use a calculator or Z score table. The Z-score for 1.5 is ..9332, the area up to that point. And 1-.9332 = .0668 or 6.68% chance.  We subtract from 1 as the question asked for the chance of a 'greater' result.   You will get he same answer by using a Z value of -1.5 with no need to subtract from 1, but that seems to confuse students a bit. \r<BR>\n" );
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document.write( "See http://users.stat.ufl.edu/~athienit/Tables/Ztable.pdf for a Z-table </SPAN>\n" );
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