document.write( "Question 1122401: Paul made a trip to the recycling plant and back. The trip there took 4 hours and the trip back took 6 hours. He averaged 25 km/h faster on the trip there than on the return trip. What was paul's average speed on the outbound trip? \n" ); document.write( "
Algebra.Com's Answer #738527 by josgarithmetic(39617)\"\" \"About 
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\n" ); document.write( "Paul made a trip to the recycling plant and back. The trip there took 4 hours and the trip back took 6 hours. He averaged 25 km/h faster on the trip there than on the return trip. What was paul's average speed on the outbound trip?
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document.write( "               SPEED        TIME      DISTANCE\r\n" );
document.write( "GOING           r            4           d\r\n" );
document.write( "RETURN         r-25          6           d\r\n" );
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\n" ); document.write( "\n" ); document.write( "Same distance d each way.
\n" ); document.write( "\"4r=6%28r-25%29\"
\n" ); document.write( "Solve this.
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