document.write( "Question 1122397: maria left the mall and drove north. jimmy left one hour later driving at 24 km/h in an effort to catch up to maria. after driving for 5 hours jimmy finally caught up. find maria's average speed \n" ); document.write( "
Algebra.Com's Answer #738523 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( " SPEED TIME DISTANCE\r\n" ); document.write( "\r\n" ); document.write( "jimmy 24 5 d\r\n" ); document.write( " \r\n" ); document.write( "maria r d\r\n" ); document.write( "\r\n" ); document.write( "difference 1\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Maria's speed r is to be found. Maria's time is to be found.\r \n" ); document.write( "\n" ); document.write( "The distance they each traveled, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " SPEED TIME DISTANCE\r\n" ); document.write( "\r\n" ); document.write( "jimmy 24 5 120\r\n" ); document.write( " \r\n" ); document.write( "maria r 6 120\r\n" ); document.write( "\r\n" ); document.write( "difference 1\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Since the time difference had to be 1 hour as given, Maria going slower, had to travel for MORE time; 6 hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Her average speed:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |