document.write( "Question 1122367: A is 11 years old and B is 68 years old. in how many years will B be 4 times as old as A? \n" ); document.write( "
Algebra.Com's Answer #738482 by Theo(13342)\"\" \"About 
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A is 11 years old.
\n" ); document.write( "B is 68 years old.\r
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\n" ); document.write( "\n" ); document.write( "let the number of years be equal to x.\r
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\n" ); document.write( "\n" ); document.write( "in x years, B will be 68 + x years old.
\n" ); document.write( "in x years, A will be 11 + x years old.
\n" ); document.write( "in x years, B will be 4 * as old as A.\r
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\n" ); document.write( "\n" ); document.write( "your equation is:
\n" ); document.write( "B + x = 4 * (A + x)
\n" ); document.write( "simplify to get:
\n" ); document.write( "B + x = 4 * A + 4 * x
\n" ); document.write( "subtract 4 * x from both sides of the equation to get:
\n" ); document.write( "B + x - 4 * x = 4 * A
\n" ); document.write( "combine like terms to get:
\n" ); document.write( "B - 3 * x = 4 * A
\n" ); document.write( "subtract 4 * A from both sides of the equation and add 3 * x to both sides of the equation to get:
\n" ); document.write( "B - 4 * A = 3 * x
\n" ); document.write( "since B = 68 and A = 11, this equation becomes:
\n" ); document.write( "68 - 4 * 11 = 3 * x
\n" ); document.write( "simplify to get:
\n" ); document.write( "68 - 44 = 3 * x
\n" ); document.write( "combine like terms to get:
\n" ); document.write( "24 = 3 * x
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = 24/3 = 8\r
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\n" ); document.write( "\n" ); document.write( "your solution is B will be 4 * as old as A in 8 years.
\n" ); document.write( "in 8 years, B will be 68 + 8 = 76
\n" ); document.write( "in 8 years, A will be 11 + 8 = 19
\n" ); document.write( "4 * 19 = 76, confirming the solution is correct.\r
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