document.write( "Question 1122368: In triangle ABC, the size of angle B is 4 times the size of angle A, and the size of angle C is 1 degrees less than 5 times the size of angle A. \n" ); document.write( "

Algebra.Com's Answer #738479 by Theo(13342) $\"\"$ $\"About$

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angle B = 4 * angle A
\n" ); document.write( "angle C = 5 * angle A - 1
\n" ); document.write( "angle A + angle B + angle C = 180 becomes:
\n" ); document.write( "angle A + 4 * angle A + 5 * angle A - 1 = 180
\n" ); document.write( "combine like terms to get 10 * angle A - 1 = 180
\n" ); document.write( "add 1 to both sides fo the equation to get:
\n" ); document.write( "10 * angle A = 181
\n" ); document.write( "divide both sides of the equation by 10 to get:
\n" ); document.write( "angle A = 181 / 10
\n" ); document.write( "solve for angle A to get:
\n" ); document.write( "angle A = 18.1 degrees.
\n" ); document.write( "angle B = 4 * angle A = 72.4 degrees.
\n" ); document.write( "angle C = 5 * angle A - 1 = 89.5 degrees.
\n" ); document.write( "18.1 + 72.4 + 89.5 = 180 degrees = sum of the interior angles of triangle ABC.
\n" ); document.write( "your solution appears to be:
\n" ); document.write( "angle A = 18.1 degrees
\n" ); document.write( "angle B = 72.4 degrees
\n" ); document.write( "angle C = 89.5 degrees
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