document.write( "Question 1122327: The ship S is sighted from two lighthouses B and U which are 16 km apart. If m∠SBU= 27° and m∠SUB= 65°. Find the distance from S to the nearer lighthouse. \n" ); document.write( "
Algebra.Com's Answer #738418 by Theo(13342)\"\" \"About 
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this forms triangle SBU where angle SBU = 27 degrees and angle SUB = 65 degrees.\r
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\n" ); document.write( "\n" ); document.write( "angle BSU is equal to 180 - 27 - 65 = 88 degrees.\r
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\n" ); document.write( "\n" ); document.write( "88 + 27 + 65 = 180, as it should, since the sum of the interior angles of a triangle is 180 degrees.\r
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\n" ); document.write( "\n" ); document.write( "BU = 16 kilometers.\r
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\n" ); document.write( "\n" ); document.write( "use the law of sines to find the length of sides BS and SU.\r
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\n" ); document.write( "\n" ); document.write( "law of sines says: a/sin(A) = b/sin(B) = c/sin(C)\r
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\n" ); document.write( "\n" ); document.write( "applied to this triangle, you get 16/sin(88) = SU/sin(27) = SB/sin(65)\r
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\n" ); document.write( "\n" ); document.write( "this can be broken up into:\r
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\n" ); document.write( "\n" ); document.write( "16/sin(88) = SU/sin(27) and 16/sin(88) = SB/sin(65)\r
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\n" ); document.write( "\n" ); document.write( "cross multiply each to get:\r
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\n" ); document.write( "\n" ); document.write( "16 * sin(27) = sin(88) * SU and 16 * sin(65) = SB * sin(88)\r
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\n" ); document.write( "\n" ); document.write( "solve for SU to get SU = 16 * sin(27) / sin(88) = 7.298275633\r
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\n" ); document.write( "\n" ); document.write( "solve for SB to get SB = 16 * sin(65) / sin(88) = 14.50976355\r
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\n" ); document.write( "\n" ); document.write( "the distance from S to the nearer lighthouse is 7.298275633 kilometers.\r
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