document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1122298>Question 1122298</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the radii and coordinates of the center of the circles: (i) x^2 + y^2 - 10 = 0 (ii) 36x^2 + 36y^2 - 24x - 36y - 23 = o </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #738383 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=738383\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> rewrite the first as x^2+y^2=10<BR>\n" );
document.write( "radius is sqrt (10)<BR>\n" );
document.write( "center is (0, 0)\r<BR>\n" );
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document.write( "rewrite second as <BR>\n" );
document.write( "36x^2-24x +36 Y^2-36y=23<BR>\n" );
document.write( "divide by 36<BR>\n" );
document.write( "x^2-(2/3)x+y^2-1=23<BR>\n" );
document.write( "complete the square <BR>\n" );
document.write( "(x-(1/3))^2+(y-(1/2))^2=23+(1/9)+(1/4)<BR>\n" );
document.write( "center is (1/3, 1/2) and radius is sqrt(23 13/36) or sqrt (841/36)=29/6 or 4.8333\r<BR>\n" );
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document.write( " </SPAN>\n" );
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