document.write( "Question 1122296: How much 36% acid solution should be added to 8% acid solution to make 224 mL of a 10% acid solution? \n" ); document.write( "
Algebra.Com's Answer #738375 by josgarithmetic(39623)\"\" \"About 
You can put this solution on YOUR website!
x, volume of 36% acid
\n" ); document.write( "224-x, volume of 8% acid\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This equation is to account for the amount of pure 100% acid: \"36x%2B8%28224-x%29=10%2A224\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If divide both sides by 4,
\n" ); document.write( "\"9x%2B2%28224-x%29=10%2A56\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Simplify and solve for x.
\n" ); document.write( "\"9x%2B448-2x=560\"
\n" ); document.write( "\"7x=560-448\"
\n" ); document.write( "\"7x=112\"
\n" ); document.write( "\"x=16\"---------volume of the 36% acid to use\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"208\"----------volume of the 8% acid to use\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(the results should be rechecked)
\n" ); document.write( "
\n" );