document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1122282>Question 1122282</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2 LINEAR EQUATIONS IN 2 UNKNOWNS or SIMULTANEOUS LINEAR EQUATIONS IN 2 UKNOWNS\r<BR>\n" );
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document.write( "if twice the length of a rectangle is increased by three times the width, the sum is 48 feet. The perimeter is 40 feet what are the dimensions of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #738373 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=738373\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "(1) Twice the length of a rectangle increased by three times the width is 48 feet: 2w+3l = 48<br><BR>\n" );
document.write( "(2) The perimeter is 40 feet: 2w+2l = 40<br><BR>\n" );
document.write( "Either by looking at those equations, or by thinking logically about the given information, the difference between those two measurements is the width of the rectangle.<br><BR>\n" );
document.write( "Finishing the problem from there should be easy. </SPAN>\n" );
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