document.write( "Question 1122260: A shipment of 10 times has 2 defective and 8 non defective items. in the inspection of the shipment, a sample of items will be selected and tested. if a defective item is found, the shipment of 10 items will be rejected.If a sample of 3 items is selected,What is the probability that the shipment will be rejected. \n" ); document.write( "
Algebra.Com's Answer #738332 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
2C1*8C2/10C3 is probability of one defective item, and that is 2*28/120=56/120
\n" ); document.write( "or
\n" ); document.write( "(2/10)(8/9)(7/8)+(8/10)(7/9)(2/8)+(8/10)(2/9)(7/8)=336/720=56/120\r
\n" ); document.write( "\n" ); document.write( "For 2 defective items
\n" ); document.write( "3C2*7C0/10C3=3/120
\n" ); document.write( "The probability of rejection is 59/120=0.492
\n" ); document.write( "
\n" );