document.write( "Question 101121: the perimeter of rectangle 240 cm. its length is decreased by 10% & its breadth increased by 20 we get the same perimeter find the length & breadth of rectangle \n" ); document.write( "
Algebra.Com's Answer #73832 by ankor@dixie-net.com(22740)\"\" \"About 
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the perimeter of rectangle 240 cm. its length is decreased by 10% & its breadth increased by 20 we get the same perimeter find the length & breadth of rectangle
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\n" ); document.write( "I don't think that this will be possible if you increase the width by 20, If
\n" ); document.write( "you mean 20% it becomes a do-able problem.
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\n" ); document.write( "Original rectangle
\n" ); document.write( "2L + 2W = 240
\n" ); document.write( "Simplify, divide by 2:
\n" ); document.write( "L + W = 120
\n" ); document.write( "L = (120-W)
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\n" ); document.write( "New rectangle
\n" ); document.write( "(L-.1L) + (W+.2W) = 120
\n" ); document.write( ".9L + 1.2W = 120
\n" ); document.write( ".9L + 1.2W = 120
\n" ); document.write( ".9L + 1.2W = 120
\n" ); document.write( ":
\n" ); document.write( "substitute (120-W for L
\n" ); document.write( ".9(120-W) + 1.2W = 120
\n" ); document.write( "108 - .9W + 1.2W = 120
\n" ); document.write( "1.2W - .9W = 120 - 108
\n" ); document.write( ".3W = 12
\n" ); document.write( "W = 12/.3
\n" ); document.write( "W = 40
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\n" ); document.write( "L = 120 - 40 = 80 cm
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\n" ); document.write( "Check by finding new rectangle dimension:
\n" ); document.write( ".9 * 80 = 72; 1.2 * 40 = 48
\n" ); document.write( "2(72) + 2(48) = 240\r
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