document.write( "Question 1121989: Last year, Maria had $30,00
\n" ); document.write( " to invest. She invested some of it in an account that paid 5%
\n" ); document.write( "simple interest per year, and she invested the rest in an account that paid 9%
\n" ); document.write( " simple interest per year. After one year, she received a total of $1780
\n" ); document.write( " in interest. How much did she invest in each account?
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Algebra.Com's Answer #738267 by Boreal(15235)\"\" \"About 
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x=amount at 5%
\n" ); document.write( "30000-x=amount at 9%
\n" ); document.write( ".05x+.09(30000-x)=1780
\n" ); document.write( ".05x+2700-.09x=1780
\n" ); document.write( "-0.04x=-920
\n" ); document.write( "x=$23000 at 5%=$1150
\n" ); document.write( "30000-x=$7000@9%=$630
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