document.write( "Question 1122162: Stu hiked a trail at an average rate of 3 miles per hour. He ran back on the same trail at an average rate of 5 miles per hour. He traveled for a total of 3 hours.\r
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Algebra.Com's Answer #738238 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "                   SPEED      TIME      DISTANCE\r\n" );
document.write( "HIKE                3          d/3        d\r\n" );
document.write( "RAN                 5          d/5        d\r\n" );
document.write( "TOTAL                          3\r\n" );
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\n" ); document.write( "This information allows for finding the one-way distance, d.
\n" ); document.write( "\"d%2F3%2Bd%2F5=3\", from which the time each way can be found.\r
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document.write( "                   SPEED      TIME      DISTANCE\r\n" );
document.write( "HIKE                3          h        3h=d      \r\n" );
document.write( "RAN                 5         3-h       5(3-h)=d\r\n" );
document.write( "TOTAL                          3\r\n" );
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\n" ); document.write( "This information as arranged allows to find the hiking time, h.
\n" ); document.write( "Note, \"HIKE\" and \"RAN\" are the same distance.\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%283h=5%283-h%29%29\"
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