document.write( "Question 1122087: Hotel A and Hotel B Had a total of 6500 guests. After 3/4 of the guests in Hotel a and 3/5 of the guests in hotel B checked out, there were 260 more guests In Hotel B than in hotel A. How many guests did Hotel A have at first? \n" ); document.write( "
Algebra.Com's Answer #738145 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let a = no.of guests in Hotel A \n" ); document.write( "let b = no. of guests in Hotel B \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement \n" ); document.write( ": \n" ); document.write( "Hotel A and Hotel B Had a total of 6500 guests. \n" ); document.write( "a + b = 6500 \n" ); document.write( "b = (6500-a) \n" ); document.write( ": \n" ); document.write( " After 3/4 of the guests in Hotel a and 3/5 of the guests in hotel B checked out, there were 260 more guests In Hotel B than in hotel A. \n" ); document.write( "That means 2/5 in Hotel B and 1/4 in Hotel A remain \n" ); document.write( " \n" ); document.write( "multiply equation by 20, cancel the denominators \n" ); document.write( "4(2b) - 5a = 260 * 20 \n" ); document.write( "8b - 5a = 5200 \n" ); document.write( "replace b with (6500-a) \n" ); document.write( "8(6500-a) - 5a = 5200 \n" ); document.write( "52000 - 8a - 5a = 5200 \n" ); document.write( "-13a = 5200 - 52000 \n" ); document.write( "-13a = -46800 \n" ); document.write( "a = \n" ); document.write( "a = 3600 guests originally in Hotel A \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "Check; find the no. guests in B: 6500 - 2600 = 2900, (1/4) of 3600 = 900 \n" ); document.write( " \n" ); document.write( "1160 - 900 = 260\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |