document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1122088>Question 1122088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Anson had 5/7 the number of marbles Joel<BR>\n" );
document.write( "Has. If Joel gives Anson 360 marbles, Anson will have twice as many marbles as Joel. How many marbles do they have together?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #738140 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=738140\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font color=\"black\" face=\"times\" size=\"3\"><BR>\n" );
document.write( "x = amount of marbles Anson has currently<BR>\n" );
document.write( "y = amount of marbles Joel has currently<BR>\n" );
document.write( "x and y are positive whole numbers<BR>\n" );
document.write( "The x and y values represent the respective marble counts before Joel hands over 360 marbles\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The first equation is<BR>\n" );
document.write( "x = (5/7)*y because \"Anson had 5/7 the number of marbles Joel has\"\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "\"if Joel gives Anson 360 marbles, Anson will have twice as many marbles as Joel\" tells us that x will bump up to x+360. <BR>\n" );
document.write( "At the same time, y drops to y-360. <BR>\n" );
document.write( "Tying the two ideas together gets us this second equation<BR>\n" );
document.write( "x+360 = 2*(y-360)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Let's use substitution to find x and y<BR>\n" );
document.write( "x+360 = 2*(y-360)<BR>\n" );
document.write( "(5/7)*y+360 = 2*(y-360) ... replace x with (5/7)*y; see equation (1) above.<BR>\n" );
document.write( "(5/7)*y+360 = 2*y-2*360<BR>\n" );
document.write( "(5/7)*y+360 = 2*y-720<BR>\n" );
document.write( "7 * [ (5/7)*y+360 ] = 7*(2*y-720)<BR>\n" );
document.write( "5y+2520 = 14y-5040<BR>\n" );
document.write( "2520+5040 = 14y-5y<BR>\n" );
document.write( "7560 = 9y<BR>\n" );
document.write( "9y = 7560<BR>\n" );
document.write( "y = 7560/9<BR>\n" );
document.write( "y = 840\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Now that we know y, we can find x<BR>\n" );
document.write( "x = (5/7)*y<BR>\n" );
document.write( "x = (5/7)*840<BR>\n" );
document.write( "x = 600\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Before the transfer, Anson has 600 marbles and Joel has 840 marbles<BR>\n" );
document.write( "After the transfer, Anson has 960 marbles and Joel has 480 marbles (600+360 = 960; 840-360=480)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "No matter what point in time you're at (before or after the transfer), there is a total of 1440 marbles. <BR>\n" );
document.write( "You can add 600 to 840 to get 1440, or you can add 960 to 480 to get the same answer.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<b><font color=red size=4>Final Answer: 1440</font></b><BR>\n" );
document.write( "</font> </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );