document.write( "Question 1122045: Hi
\n" ); document.write( "At 1pm a motorist left X travelling to Y at a uniform speed. Two hours later a bus driver started from X along the same road. The bus overtook the motorist at 6pm. The speed of the bus driver was 30kmper hour faster than the motorist.\r
\n" ); document.write( "\n" ); document.write( "Find the speed of the motorist.\r
\n" ); document.write( "\n" ); document.write( "Find the distance between X and Y if the bus was 60km from Y at 6pm.\r
\n" ); document.write( "\n" ); document.write( "thanks \n" ); document.write( "

Algebra.Com's Answer #738132 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "Hi
\n" ); document.write( "At 1pm a motorist left X travelling to Y at a uniform speed. Two hours later a bus driver started from X along the same road. The bus overtook the motorist at 6pm. The speed of the bus driver was 30kmper hour faster than the motorist.\r
\n" ); document.write( "\n" ); document.write( "Find the speed of the motorist.\r
\n" ); document.write( "\n" ); document.write( "Find the distance between X and Y if the bus was 60km from Y at 6pm.\r
\n" ); document.write( "\n" ); document.write( "thanks
\n" ); document.write( "

Let motorist’s speed be S
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document.write( "Then bus’ speed = S + 30
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document.write( "Motorist’s and bus’ time to get to meeting-point: 5 and 3 hours, respectively
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document.write( "We then get the following DISTANCE equation: 5S = 3(S + 30)
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document.write( "5S = 3S + 90
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document.write( "5S – 3S = 90
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document.write( "2S = 90
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document.write( "S, or motorist’s speed = \r
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document.write( "Distance from X to meeting-point: 5(45), or 3(45 + 30) = 225 km
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document.write( "Therefore, distance from X to Y = 
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document.write( "IGNORE all other INCORRECT or otherwise RUBBISH-ANSWERS!! \n" );
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