document.write( "Question 1122077: A study on the delivery time of mail between two locations has found that the data follows a normal distribution. The study has also found that on average, mail takes up to five days to arrive with a standard deviation of 0.75 days. Using this information, what is the probability that the mail will take at most 4 days to arrive?\r
\n" ); document.write( "\n" ); document.write( "A) 0.0918
\n" ); document.write( "B) 0.9082
\n" ); document.write( "C) 0.50
\n" ); document.write( "D) 0.4082
\n" ); document.write( "E) 1.00
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Algebra.Com's Answer #738131 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Use a table or a calculator such as this one provided at the link below\r
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\n" ); document.write( "\n" ); document.write( "http://onlinestatbook.com/2/calculators/normal_dist.html\r
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\n" ); document.write( "\n" ); document.write( "I prefer a calculator option because it's faster, more efficient, less error prone, etc. If you use the calculator at the link, then type in 5 for the mean, 0.75 for the SD (Standard Deviation) and click the \"below\" button. In the box next to \"below\", type in 4. All of this will compute \"P%28X+%3C=+4%29\"\r
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\n" ); document.write( "\n" ); document.write( "Using the calculator, we see that the answer is 0.0912 which is fairly close to 0.0918; chances are that your teacher is having you use a Z table, which might explain the slight discrepancy
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