document.write( "Question 1122017: A survey found that​ women's heights are normally distributed with mean 63.4 in. and standard deviation 2.6 in. The survey also found that​ men's heights are normally distributed with a mean 67.5 in. and standard deviation 2.8. Complete parts a through c below.
\n" ); document.write( "a. Most of the live characters at an amusement park have height requirements with a minimum of 4 ft 8 in. and a maximum of 6 ft 4 in. Find the percentage of women meeting the height requirement.
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Algebra.Com's Answer #738127 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Calculate your Z-scores. Look up the Low-end score probability and subtract it from the high-end score. Do a reality check on your results, you are nearly 3-sigma on the low end and nearly 5-sigma on the high end. Hence your answer has to be in the very high 90s. Provided the given mean and standard deviation are accurate, it would be extremely rare to find a woman who would be disqualified because of height.
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\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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