document.write( "Question 1122069: A Cape Town courier service promises that 80%of Johannesburg-bound parcel deliveries will reach their destinations within 12 hours. What is the probability that of the seven parcels sent at random times by a particular client in Cape Town, only one is delivered late? \r
\n" ); document.write( "\n" ); document.write( "I worked that out and got an answer of 0,3670. I just need help with the second part which is...\r
\n" ); document.write( "\n" ); document.write( "What is the probability of the seven parcels sent at random times by a particular client in Cape Town, only one is delivered within 12 hours?
\n" ); document.write( "A) 0.0004
\n" ); document.write( "B) 0.2753
\n" ); document.write( "C) 0.2097
\n" ); document.write( "D) 0.0043
\n" ); document.write( "E) 0.3670\r
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\n" ); document.write( "\n" ); document.write( "Thank You
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Algebra.Com's Answer #738116 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
i believe this is a binomial probability type problem.
\n" ); document.write( "the formula is p(x) = p^x * q^(n-x) * c(n,x)\r
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\n" ); document.write( "\n" ); document.write( "p is the probability of success.
\n" ); document.write( "q is the probability of failure = 1 - p
\n" ); document.write( "x is the number of successes
\n" ); document.write( "n-x is the number of failures
\n" ); document.write( "c(n,x) is the number of ways you can get sets of x out of a set of n where order is not important.\r
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\n" ); document.write( "\n" ); document.write( "p = .8
\n" ); document.write( "q = 1 - .8 = .2
\n" ); document.write( "x = 0 to 7
\n" ); document.write( "n = 7\r
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\n" ); document.write( "\n" ); document.write( "the probability that only one is late is 1 minus the probability that 6 are on time.\r
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\n" ); document.write( "\n" ); document.write( "that would be p(6) = .8^6 * .2 * c(7,6) = .3670016\r
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\n" ); document.write( "\n" ); document.write( "the probability that only one is delivered on time would be:\r
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\n" ); document.write( "\n" ); document.write( "p(1) = .8^1 * .2^6 * c(7,1) = 3.584 * 10^-4 = .0003584.\r
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\n" ); document.write( "\n" ); document.write( "round to 4 decimal places and it equals .0004.\r
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\n" ); document.write( "\n" ); document.write( "all the probabilities are listed below.\r
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\n" ); document.write( "\n" ); document.write( "the sum of all probabilities is equal to 1 as it should be.\r
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\n" ); document.write( "\n" ); document.write( "c(n,x) = n! / (x! * (n-x)!)\r
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