document.write( "Question 1122062: I've being going round and round with this question, but cannot get it right.\r
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document.write( "The weight of a body 𝑤 varies inversely with the square of its distance from the center of Earth 𝑑. If a person weighs 90 pounds on the surface of Earth, what is the person’s weight 160 miles above the surface? (Assume that the radius of Earth is 4000 miles.)\r
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document.write( "In our text it says Inversely means multiply, and so I did,(yz=k):\r
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document.write( "90(160)^2=k
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document.write( "90(25600)=k
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document.write( "2304000=k\r
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document.write( "The part of the question that has me confused is when it talks about radius of the earth being 4000 miles. \r
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document.write( "I assumed it would be used as follows:\r
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document.write( "4000m/4000 = 2304000/4000\r
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document.write( "which gives an answer of: m = 576\r
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document.write( "This seems incorrect.\r
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document.write( "Any advice would be appreciated. \r
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Algebra.Com's Answer #738100 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The weight of a body 𝑤 varies inversely with the square of its distance from the center of Earth 𝑑. If a person weighs 90 pounds on the surface of Earth, what is the person’s weight 160 miles above the surface? (Assume that the radius of Earth is 4000 miles.) \n" ); document.write( "---------- \n" ); document.write( "You have to use the distances from the Earth's center. \n" ); document.write( "--> 90*(4000/4160)^2 \n" ); document.write( "=================== \n" ); document.write( "It's a typical inverse square problem. \n" ); document.write( "Applies to gravity, sound, light, etc. \n" ); document.write( "If the distance is multiplied by x, the intensity is multiplied by 1/x^2 \n" ); document.write( " \n" ); document.write( " |