document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1122047>Question 1122047</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The number of Oranges is 3/5 the number of the papayas in the basket. If there are 16 more papayas than oranges in the basket, how many pieces of fruit of each type are they are in the basket at first? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #738079 by </B><A HREF=/tutors/aboutme.mpl?userid=Alex.33><B>Alex.33(110)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alex.33><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alex.33><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=738079\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The number of papayas=p<BR>\n" );
document.write( "The number of oranges=o\r<BR>\n" );
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document.write( "from the question we can conclude two relationships, which form a linear equation set:<BR>\n" );
document.write( "o=3p/5 (1)<BR>\n" );
document.write( "p=16+o (2)\r<BR>\n" );
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document.write( "And substitute o in (2) one by 3p/5 and get<BR>\n" );
document.write( "p=40\r<BR>\n" );
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document.write( "Use (1):<BR>\n" );
document.write( "o=24\r<BR>\n" );
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document.write( "And finally apply (2) again to confirm: 24+16=40. This shows we are going right.<BR>\n" );
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