document.write( "Question 1122019: A large rectangular movie screen in an IMAX theater has an area of 10,509 square feet. Find the dimensions of the screen if it is 20 feet longer than it is wide. \n" ); document.write( "
Algebra.Com's Answer #738056 by ikleyn(52879)\"\" \"About 
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document.write( "Let x be the number (now unknown) which is exactly half way between the width and the length of the playground.\r\n" );
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document.write( "Then, as you understand,  the length = (x+10) inches and  the width = (x-10) inches.\r\n" );
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document.write( "The area = 10509 = length*width = (x+10)*(x-10).\r\n" );
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document.write( "Thus (x+10)*(x-10) = 10509,  which implies  \"x%5E2+-+100\" = 10509,  i.e.  \"x%5E2\" = 10509+100 = 10609.\r\n" );
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document.write( "Hence, x = \"sqrt%2810609%29\" = 103.\r\n" );
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document.write( "Then the length = 103+10 = 113  and the width = 103-10 = 93.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answer. The dimensions of the screen are 113 inches and 93 inches.\r
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\n" ); document.write( "\n" ); document.write( "See the lesson\r
\n" ); document.write( "\n" ); document.write( "    - Three methods to find the dimensions of a rectangle when its area and the difference of two dimensions are given \r
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