document.write( "Question 1122003: Robin has a collection of nickels, dimes, and quarters worth $37.50. She has 30 more dimes than nickels and twice as many quarters as dimes. How many coins of each kind does she have?
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Algebra.Com's Answer #738049 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Of course, being able to set up and solve a problem like this using formal algebra is a useful skill. But solving the problem using logical analysis can be good brain exercise.

\n" ); document.write( "The number of quarters is twice the number of dimes; and the number of nickels is 30 less than the number of dimes. The total value is $37.50.

\n" ); document.write( "(1) Add 30 more nickels, so that the number of nickels is the same as the number of dimes. The total value is now $37.50 + $1.50 = $39.
\n" ); document.write( "(2) Now the numbers of dimes and nickels are the same, and the number of quarters is twice as much. So make group of 2 quarters, 1 dime, and 1 nickel; each of those group has a value of $0.65.
\n" ); document.write( "(3) The number of those groups needed to make the new total of $39 is 39/0.65 = 60.
\n" ); document.write( "(4) So with the added 30 nickels, the collection has 120 quarters, 60 dimes, and 60 nickels.
\n" ); document.write( "(5) Now take away the 30 nickels you added in the beginning to get the final answer: 120 quarters, 60 dimes, and 30 nickels.

\n" ); document.write( "CHECK:
\n" ); document.write( "120(.25)+60(.10)+30(.05) = 30.00+6.00+1.50 = 37.50
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